S-expression: Difference between revisions
→Sk*S(k + 1) (triangle-particulars): section & explain significance |
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== Sk*S(k + 1) (triangle-particulars) == | == Sk*S(k + 1) (triangle-particulars) == | ||
=== Significance === | === Significance === | ||
1. Every triangle-particular is superparticular, so these are efficient commas. (See also the [[# | 1. Every triangle-particular is superparticular, so these are efficient commas. (See also the [[#Short proof of the superparticularity of triangle-particulars]].) | ||
2. Often each individual triangle-particular, taken as a comma, implies other useful equivalences not necessarily corresponding to the general form, speaking of which... | 2. Often each individual triangle-particular, taken as a comma, implies other useful equivalences not necessarily corresponding to the general form, speaking of which... | ||