Nicetone: Difference between revisions

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| <math>\displaystyle \frac{4}{7} < G_\text{1} < \frac{2}{3}</math>

|-

! RH inner generator (''G''2 = L + m)

! RH inner generator (''G''2R = L + m)

| <math>\displaystyle \frac{1}{2} G_\text{1} < G_\text{2} < 4 G_\text{1} - 2 \text{ for } \frac{4}{7} < G_\text{1} ≤ \frac{3}{5}</math> <math>\displaystyle \frac{1}{2} G_\text{1} < G_\text{2} < 1 - G_\text{1} \text{ for }\frac{3}{5} ≤ G_\text{1} < \frac{2}{3}</math>

| <math>\displaystyle \frac{1}{2} G_\text{1} < G_\text{2R} < 4 G_\text{1} - 2 \text{ for } \frac{4}{7} < G_\text{1} ≤ \frac{3}{5}</math> <math>\displaystyle \frac{1}{2} G_\text{1} < G_\text{2R} < 1 - G_\text{1} \text{ for }\frac{3}{5} ≤ G_\text{1} < \frac{2}{3}</math>

|-

! LH inner generator (''G''2 = L + s)

! LH inner generator (''G''2L = L + s)

| <math>\displaystyle 2 - 3 G_\text{1} < G_\text{2} < \frac{1}{2} G_\text{1} \text{ for }\frac{4}{7} < G_\text{1} ≤ \frac{3}{5}</math> <math>\displaystyle 2 G_\text{1} - 1 < G_\text{2} < \frac{1}{2} G_\text{1} \text{ for }\frac{3}{5} ≤ G_\text{1} < \frac{2}{3}</math>

| <math>\displaystyle 2 - 3 G_\text{1} < G_\text{2L} < \frac{1}{2} G_\text{1} \text{ for }\frac{4}{7} < G_\text{1} ≤ \frac{3}{5}</math> <math>\displaystyle 2 G_\text{1} - 1 < G_\text{2L} < \frac{1}{2} G_\text{1} \text{ for }\frac{3}{5} ≤ G_\text{1} < \frac{2}{3}</math>

|-

! Large step (L = 2''G''1 - 1)

| <math>\displaystyle \frac{1}{7} < L < \frac{1}{3}</math>

|-

! Middle step (m = 1 - ''G''1 - ''G''2L)

| <math>\displaystyle \frac{1}{4} (1 - 3 L) < M < L \text{ for } \frac{1}{7} < L ≤ \frac{1}{5}</math> <math>\displaystyle \frac{1}{4} (1 - 3 L) < M < \frac{1}{2} (1 - 3 L) \text{ for } \frac{1}{5} ≤ L < \frac{1}{3}</math>

|-

! Small step (s = 1 - ''G''1 - ''G''2R)

| <math>\displaystyle \frac{1}{2} (1 - 5 L) < S < \frac{1}{4} (1 - 3 L) \text{ for } \frac{1}{7} < L ≤ \frac{1}{5}</math> <math>\displaystyle 0 < S < \frac{1}{4} (1 - 3 L) \text{ for } \frac{1}{5} ≤ L < \frac{1}{3}</math>

|}

@@ Line 212: / Line 212: @@
 | <math>\displaystyle \frac{4}{7} &lt; G_\text{1} &lt; \frac{2}{3}</math>
 |-
-! RH inner generator <br>(''G''<sub>2</sub> = L + m)
+! RH inner generator <br>(''G''<sub>2R</sub> = L + m)
-| <math>\displaystyle \frac{1}{2} G_\text{1} &lt; G_\text{2} &lt; 4 G_\text{1} - 2 \text{ for } \frac{4}{7} &lt; G_\text{1} &le; \frac{3}{5}</math> <br><math>\displaystyle \frac{1}{2} G_\text{1} &lt; G_\text{2} &lt; 1 - G_\text{1} \text{ for }\frac{3}{5} &le; G_\text{1} &lt; \frac{2}{3}</math>
+| <math>\displaystyle \frac{1}{2} G_\text{1} &lt; G_\text{2R} &lt; 4 G_\text{1} - 2 \text{ for } \frac{4}{7} &lt; G_\text{1} &le; \frac{3}{5}</math> <br><math>\displaystyle \frac{1}{2} G_\text{1} &lt; G_\text{2R} &lt; 1 - G_\text{1} \text{ for }\frac{3}{5} &le; G_\text{1} &lt; \frac{2}{3}</math>
 |-
-! LH inner generator <br>(''G''<sub>2</sub> = L + s)
+! LH inner generator <br>(''G''<sub>2L</sub> = L + s)
-| <math>\displaystyle 2 - 3 G_\text{1} &lt; G_\text{2} &lt; \frac{1}{2} G_\text{1} \text{ for }\frac{4}{7} &lt; G_\text{1} &le; \frac{3}{5}</math> <br><math>\displaystyle 2 G_\text{1} - 1 &lt; G_\text{2} &lt; \frac{1}{2} G_\text{1} \text{ for }\frac{3}{5} &le; G_\text{1} &lt; \frac{2}{3}</math>
+| <math>\displaystyle 2 - 3 G_\text{1} &lt; G_\text{2L} &lt; \frac{1}{2} G_\text{1} \text{ for }\frac{4}{7} &lt; G_\text{1} &le; \frac{3}{5}</math> <br><math>\displaystyle 2 G_\text{1} - 1 &lt; G_\text{2L} &lt; \frac{1}{2} G_\text{1} \text{ for }\frac{3}{5} &le; G_\text{1} &lt; \frac{2}{3}</math>
+|-
+! Large step <br>(L = 2''G''<sub>1</sub> - 1)
+| <math>\displaystyle \frac{1}{7} &lt; L &lt; \frac{1}{3}</math>
+|-
+! Middle step <br>(m = 1 - ''G''<sub>1</sub> - ''G''<sub>2L</sub>)
+| <math>\displaystyle \frac{1}{4} (1 - 3 L) &lt; M &lt; L \text{ for } \frac{1}{7} &lt; L &le; \frac{1}{5}</math> <br><math>\displaystyle \frac{1}{4} (1 - 3 L) &lt; M &lt; \frac{1}{2} (1 - 3 L) \text{ for } \frac{1}{5} &le; L &lt; \frac{1}{3}</math>
+|-
+! Small step <br>(s = 1 - ''G''<sub>1</sub> - ''G''<sub>2R</sub>)
+| <math>\displaystyle \frac{1}{2} (1 - 5 L) &lt; S &lt; \frac{1}{4} (1 - 3 L) \text{ for } \frac{1}{7} &lt; L &le; \frac{1}{5}</math> <br><math>\displaystyle 0 &lt; S &lt; \frac{1}{4} (1 - 3 L) \text{ for } \frac{1}{5} &le; L &lt; \frac{1}{3}</math>
 |}