S-expression: Difference between revisions
m →Sk/S(k+1) (ultraparticulars): trying to fix redirect to appropriate section |
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((3k+3)/(3k))/((3k+2)/(3k+1))<sup>3</sup> = (k+1)/k / ((3k+2)/(3k+1))<sup>3</sup> | ((3k+3)/(3k))/((3k+2)/(3k+1))<sup>3</sup> = (k+1)/k / ((3k+2)/(3k+1))<sup>3</sup> | ||
Also note that if you temper multiple adjacent ultraparticulars, you sometimes aren't required to use those ultraparticulars in the comma list | Also note that if you temper multiple adjacent ultraparticulars, you sometimes aren't required to use those ultraparticulars in the comma list as description of (the bulk of) the tempering may be possible through [[#Sk/S(k+2) (semiparticulars)|semiparticulars]], discussed next. | ||
== Sk/S(k+2) (semiparticulars) == | == Sk/S(k+2) (semiparticulars) == | ||