Aura
Joined 31 August 2020
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Userminusone (talk | contribs) Finally replying to Aura's question |
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== A potentially useful thing I came up with... == | == A potentially useful thing I came up with... == | ||
Hey Aura, I have another thing that I would like you to check out and give me your thoughts on. It might be more up your alley as it is based on Just Intonation. It's called the [[Userminusone/Averiant|Averiant]]. --[[User:Userminusone|Userminusone]] ([[User talk:Userminusone|talk]]) 22:46, 25 July 2021 (UTC) | Hey Aura, I have another thing that I would like you to check out and give me your thoughts on. It might be more up your alley as it is based on Just Intonation. It's called the [[User:Userminusone/Averiant|Averiant]]. --[[User:Userminusone|Userminusone]] ([[User talk:Userminusone|talk]]) 22:46, 25 July 2021 (UTC) | ||
: I checked it out and I'm not sure what to make of it at the moment. --[[User:Aura|Aura]] ([[User talk:Aura|talk]]) 14:43, 26 July 2021 (UTC) | : I checked it out and I'm not sure what to make of it at the moment. --[[User:Aura|Aura]] ([[User talk:Aura|talk]]) 14:43, 26 July 2021 (UTC) | ||
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::: I believe that, but how do you specifically narrow your commas down to those with low prime limit? --[[User:Aura|Aura]] ([[User talk:Aura|talk]]) 23:11, 26 July 2021 (UTC) | ::: I believe that, but how do you specifically narrow your commas down to those with low prime limit? --[[User:Aura|Aura]] ([[User talk:Aura|talk]]) 23:11, 26 July 2021 (UTC) | ||
:::: Sorry for the late reply, but to answer your question, one thing you could do is start with three simple ratios and find the averiantal percentage of the middle ratio relative to the two outer ratios, which you can then use to derive the comma. As an example, I could calculate the (1/1 - 5/4)averiantal percentage of 8/7, which is 3/5. To derive a comma from this, I would equate (8/7)^5 with (5/4)^3, resulting in the [[rainy comma]]. --[[User:Userminusone|Userminusone]] ([[User talk:Userminusone|talk]]) 20:25, 1 August 2021 (UTC) |