Aura
Joined 31 August 2020
Userminusone (talk | contribs) Finally replying to Aura's question |
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:::: Sorry for the late reply, but to answer your question, one thing you could do is start with three simple ratios and find the averiantal percentage of the middle ratio relative to the two outer ratios, which you can then use to derive the comma. As an example, I could calculate the (1/1 - 5/4)averiantal percentage of 8/7, which is 3/5. To derive a comma from this, I would equate (8/7)^5 with (5/4)^3, resulting in the [[rainy comma]]. --[[User:Userminusone|Userminusone]] ([[User talk:Userminusone|talk]]) 20:25, 1 August 2021 (UTC) | :::: Sorry for the late reply, but to answer your question, one thing you could do is start with three simple ratios and find the averiantal percentage of the middle ratio relative to the two outer ratios, which you can then use to derive the comma. As an example, I could calculate the (1/1 - 5/4)averiantal percentage of 8/7, which is 3/5. To derive a comma from this, I would equate (8/7)^5 with (5/4)^3, resulting in the [[rainy comma]]. --[[User:Userminusone|Userminusone]] ([[User talk:Userminusone|talk]]) 20:25, 1 August 2021 (UTC) | ||
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Please remember to add a link in the ''EDO'' page when you create new edo pages. [[User:FloraC|FloraC]] ([[User talk:FloraC|talk]]) 09:08, 23 December 2022 (UTC) | |||