Talk:Superparticular ratio: Difference between revisions

Frostburn (talk | contribs)
Is the etymology correct?
 
(3 intermediate revisions by 2 users not shown)
Line 23: Line 23:


I'm by no means an expert in Latin, but doesn't ''superparticular'' mean ''"above a part"'' or ''"the next after a part"''. The ''supering'' is done by 1 and not by 1/n as in ''"above (unity) by one part"''. -[[User:Frostburn|Frostburn]] ([[User talk:Frostburn|talk]]) 12:17, 23 May 2024 (UTC)
I'm by no means an expert in Latin, but doesn't ''superparticular'' mean ''"above a part"'' or ''"the next after a part"''. The ''supering'' is done by 1 and not by 1/n as in ''"above (unity) by one part"''. -[[User:Frostburn|Frostburn]] ([[User talk:Frostburn|talk]]) 12:17, 23 May 2024 (UTC)
: Yes, the etymology is correct; I know because I'm the one who brought it to the wiki from the work by Thomas Taylor cited in the references. So I don't exactly understand the nature of your confusion, I'm afraid, but perhaps things will be clarified if you review the [[Superparticular ratio#Generalizations|Generalizations]] section of the page. The "part" ''is'' the 1, which is why a super''bi''particular is of the form (n+2)/n. Happy to try to explain further if it's still unclear, and also work to revise the page to avoid any ambiguity or implicitness. I remember this was really confusing and unintuitive and surprising to me when Dave first tried to explain it to me. --[[User:Cmloegcmluin|Cmloegcmluin]] ([[User talk:Cmloegcmluin|talk]]) 15:07, 23 May 2024 (UTC)
== Multiplex ratios ==
We might add to superparticular (n+1:n) and superpartient ratios mulitplex ratios (n:1). Examples of multiplex ratios would be the 2/1 octave and 3/1 twelfth. [[User:Mschulter1325|Mschulter1325]] 06:12, 6 June 2024 (UTC)
: I think [[Harmonic]] is the page you wanna work on. [[User:FloraC|FloraC]] ([[User talk:FloraC|talk]]) 14:03, 6 June 2024 (UTC)
Return to "Superparticular ratio" page.