Defactoring algorithms: Difference between revisions
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This is a form of 5-limit [[porcupine]], a [[rank-2]] | This is a form of 5-limit [[porcupine]], a [[rank-2 temperament]] (in fact it is the result of putting it into [[IRREF]]). Looking at either row, neither map has a common factor. But remember that we also need to check linear combinations of rows. If we subtract the 2nd row from the 1st row, we can produce the row {{map| 3 -3 -6 }}, which has a common factor of 3. So this mapping is also enfactored, even though it is not obvious from just looking at it. | ||
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