5041/5040: Difference between revisions

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== Theory ==
== Theory ==
5041/5040 represents the difference between 72/71 and 71/70. It is also the answer to the Brocard's problem question of n! + 1 = m^2, to which there's only three known so far - [[25/24]], [[121/120]], and this.
5041/5040 represents the difference between [[72/71]] and [[71/70]]; therefore tempering this comma out splits their product, [[36/35]], in two; as 36/35 is the ratio of [[6/5]] to [[7/6]], tempering out this comma also splits [[7/5]] in two, by equating [[84/71]] to [[71/60]]. It is also a solution to Brocard's problem, n! + 1 = m^2, for which there are only three known answers: [[25/24]], [[121/120]], and this.


== References ==
== References ==


* Wikipedia Contributors, [[Wikipedia:Brocard's problem|Brocard's problem]].
* Wikipedia Contributors, [[Wikipedia:Brocard's problem|Brocard's problem]].
[[Category:Commas referencing a famous use of a number]]

Latest revision as of 23:46, 2 March 2026

Interval information
Ratio 5041/5040
Subgroup monzo 2.3.5.7.71 [-4 -2 -1 -1 2
Size in cents 0.3434647¢
Names third brown pair comma,
19th highly compositema
Color name 71oorg1
FJS name [math]\displaystyle{ \text{P1}^{71,71}_{5,7} }[/math]
Special properties square superparticular,
reduced
Tenney norm (log2 nd) 24.5987
Weil norm (log2 max(n, d)) 24.599
Wilson norm (sopfr(nd)) 168
Comma size unnoticeable
S-expression S71
Open this interval in xen-calc

5041/5040, the third brown pair comma, or the 19th highly compositema is a 71-limit superparticular interval measuring about 343 millicents.

Theory

5041/5040 represents the difference between 72/71 and 71/70; therefore tempering this comma out splits their product, 36/35, in two; as 36/35 is the ratio of 6/5 to 7/6, tempering out this comma also splits 7/5 in two, by equating 84/71 to 71/60. It is also a solution to Brocard's problem, n! + 1 = m^2, for which there are only three known answers: 25/24, 121/120, and this.

References