Talk:S-expression: Difference between revisions
Created page with "== I prefer a much bruter method to show the semiparticulars' superparticularity == {| class="wikitable" |+Demonstration of semiparticulars' superparticularity | If ''k'' = 4..." |
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So we see for ''k'' = 4''n'', 4''n'' + 1, and 4''n'' - 2, a coefficient of 2<sup>2</sup> is canceled out, whereas for the ''k'' = 4''n'' - 1, a coefficient of 2 is canceled out. [[User:FloraC|FloraC]] ([[User talk:FloraC|talk]]) 18:31, 7 February 2022 (UTC) | So we see for ''k'' = 4''n'', 4''n'' + 1, and 4''n'' - 2, a coefficient of 2<sup>2</sup> is canceled out, whereas for the ''k'' = 4''n'' - 1, a coefficient of 2 is canceled out. [[User:FloraC|FloraC]] ([[User talk:FloraC|talk]]) 18:31, 7 February 2022 (UTC) | ||
: I figured something like this would be possible but I sometimes get lost in how to simplify and group stuff in intermediate steps when I do it that way or I make mistakes simplifying/expanding so I tried to use the most intuitive approach I could think of. The observation that k=2n leads to a factor of 4 I think is a relatively intuitive explanation of why its superparticular for those cases. Also, it took me a little while but I believe S(k)/S(k+2) = (k+3)/(k-1) * k<sup>2</sup>/(k+2)<sup>2</sup> is the equation you substituted into for the four cases? (Just arranged as one single fraction.) --[[User:Godtone|Godtone]] ([[User talk:Godtone|talk]]) 23:45, 7 February 2022 (UTC) | |||