Hexany: Difference between revisions

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== Example ==
== Example ==


Here is a step-by-step construction of the canonical 1-3-5-7 hexany (i.e. using [[1/1]], [[3/1]], [[5/1]], and [[7/1]] with 1/1 as the root):
Here is a step-by-step construction of the canonical 1-3-5-7 hexany (i.e. using [[1/1]], [[3/1]], [[5/1]], and [[7/1]] with the smallest product as the root):
# Multiply together each pair of intervals (to find the combinations):<br>{1 × 3, 1 × 5, 1 × 7, 3 × 5, 3 × 7, 5 × 7}<br> = {3, 5, 7, 15, 21, 35};
# Multiply together each pair of intervals (to find the combinations):<br>{1 × 3, 1 × 5, 1 × 7, 3 × 5, 3 × 7, 5 × 7}<br> = {3, 5, 7, 15, 21, 35};
# Divide each product by the smallest element of the previous set (to base the scale on 1/1):<br>{3/3, 5/3, 7/3, 15/3, 21/3, 35/3}<br>= {1/1, 5/3, 7/3, 5/1, 7/1, 35/3};
# Divide each product by the smallest element of the previous set (to base the scale on 1/1):<br>{3/3, 5/3, 7/3, 15/3, 21/3, 35/3}<br>= {1/1, 5/3, 7/3, 5/1, 7/1, 35/3};

Revision as of 21:32, 7 August 2021

A hexany is a 6-note scale built using all the possible combinations of 2 intervals from a given set of 4 intervals. It is the simplest case of a combination product set.

Example

Here is a step-by-step construction of the canonical 1-3-5-7 hexany (i.e. using 1/1, 3/1, 5/1, and 7/1 with the smallest product as the root):

  1. Multiply together each pair of intervals (to find the combinations):
    {1 × 3, 1 × 5, 1 × 7, 3 × 5, 3 × 7, 5 × 7}
    = {3, 5, 7, 15, 21, 35};
  2. Divide each product by the smallest element of the previous set (to base the scale on 1/1):
    {3/3, 5/3, 7/3, 15/3, 21/3, 35/3}
    = {1/1, 5/3, 7/3, 5/1, 7/1, 35/3};
  3. Octave-reduce each element:
    {1/1, 5/3, 7/6, 5/4, 7/4, 35/24};
  4. Sort the elements in ascending order:
    {1/1, 7/6, 5/4, 35/24, 5/3, 7/4};
  5. Replace the unison (1/1) by the octave (2/1) for a Scala-compatible octave-repeating scale:
    {7/6, 5/4, 35/24, 5/3, 7/4, 2/1}.

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