Delta-rational chord: Difference between revisions

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=== Naive least-squares error ===
=== Naive least-squares error ===
Rewriting a bit, if 1:''r''<sub>1</sub>:''r''<sub>2</sub>:...:''r''<sub>''n''</sub> has delta signature +ε<sub>1</sub> +ε<sub>2</sub> ... +ε<sub>''n''</sub> (where the chord is 1:1+ε<sub>1</sub>:...), let <math>D_i = \sum_{k=1}^i \delta_i</math> and <math>E_i = \sum_{k=1}^i \epsilon_i.</math> Then the resulting linear least-squares optimization problem is
Rewriting a bit, if 1:''r''<sub>1</sub>:''r''<sub>2</sub>:...:''r''<sub>''n''</sub> has delta signature +ε<sub>1</sub> +ε<sub>2</sub> ... +ε<sub>''n''</sub> (where the chord is 1:1+ε<sub>1</sub>:...), let <math>D_i = \sum_{k=1}^i \delta_i</math> (the ''target'' delta signature) and <math>E_i = \sum_{k=1}^i \epsilon_i</math> (the ''approximant'' delta signature). Then the resulting linear least-squares optimization problem is


<math>
<math>
  \displaystyle{ \min_x  \sqrt{\sum_{i=1}^n \Bigg( E_ix - D_i \Bigg)^2 } }
  \displaystyle{ \min_x  \sqrt{\sum_{i=1}^n \Bigg( D_ix - E_i \Bigg)^2 } }
</math>
</math>


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<math>
<math>
x = \displaystyle{\frac{\sum_{i=1}^n D_i E_i}{\sum_{i=1}^n E_i^2},}
x = \displaystyle{\frac{\sum_{i=1}^n D_i E_i}{\sum_{i=1}^n D_i^2},}
</math>
</math>