Expanding tonal space/planar extensions: Difference between revisions
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::::<math> | ::::<math> | ||
r_{cents}= ln(r)\cdot\frac{1200}{ln(2)} \approx 1902</math> ¢ | r_{cents}= ln(r)\cdot\frac{1200}{ln(2)} \approx 1902</math> ¢ | ||
==== Pentave ==== | |||
In a Mode '''2<sup>-2'''</sup> (=0.25) overtone scale the first interval above the fundamental is the [[pentave]] (5/1), which substitutes the octave (2/1), the first interval in the Mode 1 overtone scale. This fractional mode of the overtone scale contains no octaves. It contains only odd harmonics with a spacing of 4 (e.g. 5, 9, 13, 17, 21, 25). | |||
::::<math> | |||
r=\frac{0.25+1}{0.25}=\frac{5}{1}</math> | |||
::::<math> | |||
r_{cents}= ln(r)\cdot\frac{1200}{ln(2)} \approx 2786</math> ¢ | |||
==== Double octave ==== | |||
In a Mode'''''(1/3)''''' overtone scale the first interval above the fundamental is the [[4/1|double octave]] (4/1), sometimes called the ''tetrave''. It substitutes the octave (2/1), the first interval in the Mode 1 overtone scale. | |||
This fractional mode of the overtone scale contains every second octave. Octaves with 1200 ¢, 3600 ¢,… are not present in this mode. It contains harmonics with a spacing of 3 (e.g. 4, 7, 10, 13, 16). | |||
::::<math> | |||
r=\frac{\frac{1}{3}+1}{\frac{1}{3}}=\frac{4}{1}</math> | |||
::::<math> | |||
r_{cents}= ln(r)\cdot\frac{1200}{ln(2)} = 2400</math> ¢ | |||
To find the exponent x for the mode number in exponential form we solve <math>2^x\,=\frac{1}{3}</math> for x: | |||
::::<math>x = \frac{ln(\frac{1}{3})}{ln(2)} \approx -1.585</math> | |||
== Find out more about tonal space… == | |||
====[[Expanding tonal space|Part I: Expanding tonal space]]==== | |||
== See also... == | |||
[[OS|Otonal sequence]] (OS) | |||