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LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)
LLsLsLLsLsLs LLsLsLs (from 2nd: 7L 5s, from 3rd: 4L 3s)
</pre>
</pre>
More intense pattern. First, Imagine <math>L = 2\sqrt{2}+2</math> and <math>s = 1</math> and divide L into
<math>\qquad L_1:s_1 = 2\sqrt{2}+1:1 = [3; 1, 4, 1, 4, ...]</math>.
OK, now <math>L_1 = 2\sqrt{2}+1</math> and <math>s_1 = s = 1</math>. Next, divide L<sub>1</sub> into
<math>\qquad L_2:s_2 = 2\sqrt{2}:1 = [2; 1, 4, 1, 4, ...]</math>.
OK, now <math>L_2 = 2\sqrt{2}</math> and <math>s_2 = s = 1</math>. Next, divide L<sub>2</sub> into
<math>\qquad L_3:s_3 = 2\sqrt{2}-1:1 = [1; 1, 4, 1, 4, ...]</math>.
OK, now <math>L_3 = 2\sqrt{2}-1</math> and <math>s_3 = s = 1</math>. Next, divide L<sub>3</sub> into
<math>\qquad L_4:s_4 = 2\sqrt{2}-2:1 = [0; 1, 4, 1, 4, ...]</math>.
No, <math>L_4 < s_4</math>. Let <math>s_5 := L_4</math> and <math>L_5 := s_4</math>. (Rotate the rectangle 90°)
OK, now <math>L_5 = 1</math> and <math>s_5 = 2\sqrt{2}-2</math> and <math>L_5:s_5 = (\sqrt{2}+1) / 2 = [1; 4, 1, 4, 1, ...]</math>. Next, divide L<sub>5</sub> into
<math>\qquad L_6:s_6 = (\sqrt{2}-1)/2:1 = [0; 4, 1, 4, 1, ...]</math>.
No, <math>L_6 < s_6</math>. Let new <math>s := L_6</math> and new <math>L := s_6</math>. (Rotate the rectangle 90°)
OK, now <math>L = 2\sqrt{2}-2</math> and <math>s = 3-2\sqrt{2}</math> and <math>L:s = 2\sqrt{2}+2 = [4; 1, 4, 1, 4, ...]</math>.
Loop.
In this case, we actually can choose from five entry points.
== Generator size ==
== Generator size ==
{| class="wikitable"
{| class="wikitable"
!  !! Dividing ratio !! Generator size !! Remarks
!  !! Dividing ratio !! Generator size !! Remarks
|-
|-
| Golden || <math>L_1:s_1 = φ-1:1</math> || 458.36 (741.64) \ 1200 || logarithmic phi
| Golden || <math>L_1:s_1 = φ-1:1</math> || g = 458.36 ¢, p = 1200 ¢ || logarithmic phi
|-
|-
| Silver 1st isotope || <math>L_1:s_1 = δ_s-1:1</math> || 702.94 \ 1200 || argent fifth
| Silver 1st isotope || <math>L_1:s_1 = δ_s-1:1</math> || g = 702.94 ¢, p = 1200 ¢ || argent fifth
|-
|-
| Silver || <math>L_2:s_2 = δ_s-2:1</math> || 351.47 \ 1200|| Imaginary, argent neutral third
| Silver || <math>L_2:s_2 = δ_s-2:1</math> || g = 351.47 ¢, p = 1200 ¢|| Imaginary, argent neutral third
|-
|-
| Bimetallic (no name A-1) || <math>L_1:s_1 = \sqrt{3}:1</math> || 760.77 \ 1200 ||  
| Bimetallic (unnamed A-1) || <math>L_1:s_1 = \sqrt{3}:1</math> || g = 760.77 ¢, p = 1200 ¢ ||  
|-
|-
| Bimetallic (no name A-2) || <math>L_2:s_2 = \sqrt{3}-1:1</math> || 507.18 \ 1200|| Flattone
| Bimetallic (unnamed A-2) || <math>L_2:s_2 = \sqrt{3}-1:1</math> || g = 507.18 ¢, p = 1200 ¢ || Flattone
|-
|-
| Bimetallic (no name A-3) || <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math> || 321.54 \ 1200|| Superkleismic
| Bimetallic (unnamed A-3) || <math>L_4:s_4 = (\sqrt{3}-1)/2:1</math> || g = 321.54 ¢, p = 1200 ¢ || Superkleismic
|-
| Bimetallic (unnamed B-1) || <math>L_1:s_1 = 2\sqrt{2}+1:1</math> || g = 951.47 ¢, p = 1200 ¢ || Semaphore
|-
| Bimetallic (unnamed B-2) || <math>L_2:s_2 = 2\sqrt{2}:1</math> || g = 886.56 ¢, p = 1200 ¢ || Hanson
|-
| Bimetallic (unnamed B-3) || <math>L_3:s_3 = 2\sqrt{2}-1:1</math> || g = 775.74 ¢, p = 1200 ¢ || Squares
|-
| Bimetallic (unnamed B-4) || <math>L_4:s_4 = 2\sqrt{2}-2:1</math> || g = 543.70 ¢, p = 1200 ¢ ||
|-
| Bimetallic (unnamed B-5) || <math>L_6:s_6 = (\sqrt{2}-1)/2:1</math> || g = 205.89 ¢, p = 1200 ¢ ||  
|}
|}
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