Hypercubic billiard word

From Xenharmonic Wiki
Revision as of 04:12, 2 June 2022 by Inthar (talk | contribs)
Jump to navigation Jump to search

Billiard scales are motivated by considering a point particle (a "billiard ball") bouncing off walls in a closed cubic room. Given a scale signature a1X1 ... arXr (i.e. stipulating that our scale has r distinct, not-necessarily-linearly-independent step sizes X1, ..., Xr, and the number of Xi steps in the scale is ai), we imagine our billiard ball in an r-dimensional cubic room (with side length 1). We first fire off the billiard ball in the direction (a1, ..., ar) given by the scale signature. The particle's trajectory will be periodic, and with probability one, any collision only be with one wall at a time. The pattern of which walls the particle collides with then spells out a billiard scale.

Formal definition

Formally, let

  • w be a scale word with signature a1X1 ... arXr (i.e. w is a scale word with ai-many Xi steps);
  • n = a1 + ... + ar be the length of w;
  • L be a line of the form L(t) = (a1, ..., ar)t + v0, where v0 is a constant vector in Rr. We say that L is in generic position if L intersects the hyperplane x1 = 0 at a point (0, α1, α2, ... αr-1) where αi and αji for ij are irrational.

We call w a rank-r billiard scale if any line in generic position of the form (a1, ..., ar)t + v0 has intersections with coordinate level planes xi = kZ that spell out the scale as you move in the positive t direction along that line.

Properties

Proofs to be added

  • Mosses are rank-2 billiard scales
  • A billiard scale projects to a billiard scale of lower rank when one removes all instances of some subset of its step sizes
  • Given any r and any "nondegenerate" scale signature a1X1, ..., arXr (i.e. no ai is 0), there are only finitely many billiard scales with that signature up to rotation
    • Finiteness is obvious; how does the number of billiard scales with a given signature depend on r or with the signature?