The Riemann zeta function and tuning/Vector's derivation
We start with the mu function:
$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\operatorname{abs} \left( \operatorname{mod} \left( 2g \left( k \right) x, 2 \right) - 1 \right)}{k^{2}} $$
We start with the mu function:
$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\operatorname{abs} \left( \operatorname{mod} \left( 2g \left( k \right) x, 2 \right) - 1 \right)}{k^{2}} $$