Wedgie/Archived version: Difference between revisions

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The following additionally assumes that you know what the words "basis", "linear map", and "determinant" mean.
The following additionally assumes that you know what the words "basis", "linear map", and "determinant" mean.


Consider the 2.''q''<sub>1</sub>.(…).q<sub>''n''</sub> [[JI subgroup]], with basis '''2''', '''q'''<sub>1</sub>, ..., '''q'''<sub>''n''</sub>. (Here we use bold small letters and numbers to represent elements of the JI lattice, viewed as vectors; so, for example, 3/2 = '''3''' &minus; '''2''' in the 2.3 lattice. Italicized letters represent other numbers and sets, and roman letters represent maps.)
Consider the 2.''q''<sub>1</sub>.(…).q<sub>''n''</sub> [[JI subgroup]], with basis '''2''', '''q'''<sub>1</sub>, ..., '''q'''<sub>''n''</sub>.


The period '''p''' (fraction of octave) and generator '''g''' form a basis for all the intervals of a rank-2 temperament. For example, '''p''' = 2/1 and '''g''' = 3/2 form a basis for meantone. But from a purely linear-algebra perspective, there's nothing special about the basis {'''p''', '''g'''}; I could have chosen another basis, for example '''p'''' = 3/1 for my "period" and '''g'''' = 2/1 for my "generator". What makes the wedgie a unique identifier for a temperament is that rather than specify a basis directly, the wedgie specifies a ''constraint'' that any basis for the temperament must satisfy: namely, that a basis '''e'''<sub>1</sub>, '''e'''<sub>2</sub> must satisfy W('''e'''<sub>1</sub>, '''e'''<sub>2</sub>) = ±1.
The period '''p''' (fraction of octave) and generator '''g''' form a basis for all the intervals of a rank-2 temperament. For example, '''p''' = 2/1 and '''g''' = 3/2 form a basis for meantone. But from a purely linear-algebra perspective, there's nothing special about the basis {'''p''', '''g'''}; I could have chosen another basis, for example '''p'''' = 3/1 for my "period" and '''g'''' = 2/1 for my "generator". What makes the wedgie a unique identifier for a temperament is that rather than specify a basis directly, the wedgie specifies a ''constraint'' that any basis for the temperament must satisfy: namely, that a basis '''e'''<sub>1</sub>, '''e'''<sub>2</sub> must satisfy W('''e'''<sub>1</sub>, '''e'''<sub>2</sub>) = ±1.