Metallic MOS: Difference between revisions
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To compute the <span><math>L{:}s</math></span> sequence, we depleted terms of the generator’s continued fraction. By doing the opposite — gradually building up the generator’s continued fraction by incrementing terms — we can determine the path our generator takes through the Stern-Brocot tree. | To compute the <span><math>L{:}s</math></span> sequence, we depleted terms of the generator’s continued fraction. By doing the opposite — gradually building up the generator’s continued fraction by incrementing terms — we can determine the path our generator takes through the Stern-Brocot tree. | ||
We’ll use the example of the golden generator, with continued fraction <span><math>[0; 2, 1]</math></span>: | We’ll use the example of the golden generator, with continued fraction <span><math>[0; 2, \overline{1}]</math></span>: | ||
<math> | <math> | ||