The Riemann zeta function and tuning/Vector's derivation: Difference between revisions
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Created page with "We start with the mu function: <nowiki>$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\abs{\operatorname{mod} \left( 2\log_{2} \left( k \right) x, 2 \right) - 1}}{k^{2}} $$</nowiki>" |
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We start with the mu function: | We start with the mu function: | ||
<nowiki>$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\abs{\operatorname{mod} \left( | <nowiki>$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\abs{\operatorname{mod} \left( 2g \left( k \right) x, 2 \right) - 1}}{k^{2}} $$</nowiki> | ||
Revision as of 01:37, 10 April 2025
We start with the mu function:
$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\abs{\operatorname{mod} \left( 2g \left( k \right) x, 2 \right) - 1}}{k^{2}} $$