MOS substitution: Difference between revisions

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Open question: Is the length of the shortest guided generator sequence related to the length of the filler MOS? It could hold when the scale pattern has the divisibilities that this procedure is intended to take advantage of.
Open question: Is the length of the shortest guided generator sequence related to the length of the filler MOS? It could hold when the scale pattern has the divisibilities that this procedure is intended to take advantage of.
Open question: What guarantees that the deletion of s steps from a scale thus "aberrismized" recovers the MOS version of aLbm?

Revision as of 01:06, 20 January 2024

MOS substitution is a procedure for obtaining a ternary scale with arbitrary scale signature aLbmcs. Originally developed by Inthar for the purpose of adding aberrisma steps to a binary pattern in the context of groundfault's aberrismic theory, MOS substitution is intended to take advantage of extra symmetry when a, c or b, c is not a coprime pair and generalize the congruence substitution procedure for building balanced words to obtain non-balanced but still more "even" scales.

Take for example d = (a, c) (:= gcd(a, c)), let a' = a/d and c' = c/d. Consider the MOS word (a + c)Xbm, which we call the template MOS. The most even arrangement of a'-many L steps and c'-many s steps is the MOS a'Lc's, so this method prescribes following the latter MOS, called the filling MOS, to fill in the X's. Fixing a choice of which X in (a + c)Xbm you start from, you have to choose a mode of a'Lc's. (Todo: count the distinct choices.) If a' = c' = 1, we obtain a balanced (equivalently MV3) scale; when in addition b is odd, the scale is also SV3 and chiral, and we recover the two chiralities from the two modes of a'Lc's. Of course, one may do this using aL(b + c)X and (b/(b, c))m (c/(b, c))s instead.

For 5L2m4s, we obtain LsLsLmLsLsm, LsLmLsLsLms, and LmLsLsLmLss. The first two are a chiral pair of billiard scales, and the last is achiral but not deletion-MOS. All three scales admit short generator sequences of 2-steps, respectively GS(L+s, L+s, L+m), GS(L+s, L+m, L+s), and GS(L+m, L+s, L+s), notably representing all 3 possible rotations of (L+s, L+m, L+s).

Open question: Is the length of the shortest guided generator sequence related to the length of the filler MOS? It could hold when the scale pattern has the divisibilities that this procedure is intended to take advantage of.

Open question: What guarantees that the deletion of s steps from a scale thus "aberrismized" recovers the MOS version of aLbm?