The Riemann zeta function and tuning/Vector's derivation: Difference between revisions
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We start with the mu function: | We start with the mu function: | ||
<nowiki>$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\abs | <nowiki>$$ \mu \left( x \right) = \sum_{k=1}^{\infty} \frac{\operatorname{abs} \left( \operatorname{mod} \left( 2g \left( k \right) x, 2 \right) - 1 \right)}{k^{2}} $$</nowiki> | ||