MOS substitution: Difference between revisions

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The generator sequence thus yields ''q'' parallel chains ''C''<sub>1</sub>,  
The generator sequence thus yields ''q'' parallel chains ''C''<sub>1</sub>,  
..., ''C''<sub>q</sub> of the aggregate generator, and the offset between two adjacent chains is equal to the result of substituting the perfect generator of the filling MOS into the generator of the template MOS. Hence in the GS,
..., ''C''<sub>''q''</sub> of the aggregate generator, and the offset between ''C''<sub>''i''</sub> and ''C''<sub>''i''+1</sub> is equal to the result of substituting the perfect generator of the filling MOS into the generator of the template MOS. Hence in the GS,
* the perfect generator of the filling MOS corresponds to advancing from ''C''<sub>''i''</sub> to ''C''<sub>''i''+1</sub>
* the perfect generator of the filling MOS corresponds to advancing from ''C''<sub>''i''</sub> to ''C''<sub>''i''+1</sub>
* the imperfect generator of the filling MOS corresponds to looping back to ''C''<sub>1</sub> but on the next note of ''C''<sub>1</sub>, so it and the ''q'' &minus; 1 notes thereafter are advanced by 1 note in the chain.
* the imperfect generator of the filling MOS corresponds to looping back to ''C''<sub>1</sub> but on the next note of ''C''<sub>1</sub>, so it and the ''q'' &minus; 1 notes thereafter are advanced by 1 note in the chain.