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{| class="wikitable"
== Theorem 9 (Ternary product words) ==
|Tone class
If a [[product word]] of two MOS words of the same length is ternary, then it is pairwise-MOS.
|A (null or resonant coda) (2/6)
=== Proof ===
|B (glottal stop coda) (1/6)
Assume that the product of two MOS words ''v''('''a''', '''b''') and ''w''('''c''', '''d''') contains exactly three letters, say ('''a''', '''c'''), ('''a''', '''d'''), ('''b''', '''c'''). Equating ('''a''', '''c''') and ('''a''', '''d''') recovers ''v'', and equating ('''a''', '''c''') and ('''b''', '''c''') recovers ''w''. What does equating ('''a''', '''d''') and ('''b''', '''c''') do?
|C (fricative coda) (1/6)
|D (voiceless stop coda) (1/6)
|E (voiced stop coda) (1/6)
|-
|Modal initial (3/8)
|33 (a)
|212 ()
|22 ()
|35 (á)
|11 (a̱̱)
|-
|Breathy initial (3/8)
|31 ()
|15 ()
|343 (â)
|15 ()
|343 (â)
|-
|Creaky initial (2/8)
|51 (à)
|44 (ā)
|11 (a̱̱)
|55 (ā̄)
|51 (à)
|}