Patent val
IMPORTED REVISION FROM WIKISPACES
This is an imported revision from Wikispaces. The revision metadata is included below for reference:
- This revision was by author genewardsmith and made on 2011-01-30 22:45:53 UTC.
- The original revision id was 197306580.
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Original Wikitext content:
Given N-edo, the equal division of the octave into N parts, we may for any prime p find a corresponding p-limit val in a canonical manner by multiplying N by <1 log2(3) log2(5) ... log(p)| and rounding to the nearest integer. In general this is not guaranteed to be the most accurate available val, but if N-edo has enough relative accuracy in the p-limit, it will be. The name //patent// comes from the fact that "patent" in one sense of the word is a synonym for "obvious"; the patent val may or may not be the best choice but it's the obvious choice. For example, multiplying 12 times <1 1.585 2.322 2.807 3.459| yields <12 19.020 27.863 33.688 41.513|, which rounds off to <12 19 28 34 42|, the 11-limit patent val for 12edo.
Original HTML content:
<html><head><title>Patent val</title></head><body>Given N-edo, the equal division of the octave into N parts, we may for any prime p find a corresponding p-limit val in a canonical manner by multiplying N by <1 log2(3) log2(5) ... log(p)| and rounding to the nearest integer. In general this is not guaranteed to be the most accurate available val, but if N-edo has enough relative accuracy in the p-limit, it will be. The name <em>patent</em> comes from the fact that "patent" in one sense of the word is a synonym for "obvious"; the patent val may or may not be the best choice but it's the obvious choice.<br /> <br /> For example, multiplying 12 times <1 1.585 2.322 2.807 3.459| yields <12 19.020 27.863 33.688 41.513|, which rounds off to <12 19 28 34 42|, the 11-limit patent val for 12edo.</body></html>