0edo: Difference between revisions

From Xenharmonic Wiki
Jump to navigation Jump to search
← Older editNewer edit →
VisualWikitext
Wikispaces>PiotrGrochowski
**Imported revision 590525358 - Original comment: **
Wikispaces>davethecomposer
**Imported revision 590988684 - Original comment: **
Line 1: Line 1:
<h2>IMPORTED REVISION FROM WIKISPACES</h2>
<h2>IMPORTED REVISION FROM WIKISPACES</h2>
This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
This is an imported revision from Wikispaces. The revision metadata is included below for reference:<br>
: This revision was by author [[User:PiotrGrochowski|PiotrGrochowski]] and made on <tt>2016-08-30 11:38:11 UTC</tt>.<br>
: This revision was by author [[User:davethecomposer|davethecomposer]] and made on <tt>2016-09-02 21:28:29 UTC</tt>.<br>
: The original revision id was <tt>590525358</tt>.<br>
: The original revision id was <tt>590988684</tt>.<br>
: The revision comment was: <tt></tt><br>
: The revision comment was: <tt></tt><br>
The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.<br>
The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.<br>
Line 10: Line 10:
There are two ways to approach this idea.
There are two ways to approach this idea.


Given that //n////-//edo means that you are dividing the octave into 1///n// equal divisions and that 1/0 is undefined in kid's mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all. However, in standard mathematics, 1/0 is Infinity, therefore one step is infinite. However, it cannot be heard because it's outside human hearing range. So only one sound of 0edo can be heard.
Given that //n////-//edo means that you are dividing the octave into 1///n// equal divisions and that 1/0 is undefined in standard mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all.


The other way of looking at it is to see what happens as //n// gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As //n// gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.</pre></div>
The other way of looking at it is to see what happens as //n// gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As //n// gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.</pre></div>
Line 18: Line 18:
There are two ways to approach this idea.&lt;br /&gt;
There are two ways to approach this idea.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Given that &lt;em&gt;n&lt;/em&gt;&lt;em&gt;-&lt;/em&gt;edo means that you are dividing the octave into 1&lt;em&gt;/n&lt;/em&gt; equal divisions and that 1/0 is undefined in kid's mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all. However, in standard mathematics, 1/0 is Infinity, therefore one step is infinite. However, it cannot be heard because it's outside human hearing range. So only one sound of 0edo can be heard.&lt;br /&gt;
Given that &lt;em&gt;n&lt;/em&gt;&lt;em&gt;-&lt;/em&gt;edo means that you are dividing the octave into 1&lt;em&gt;/n&lt;/em&gt; equal divisions and that 1/0 is undefined in standard mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
The other way of looking at it is to see what happens as &lt;em&gt;n&lt;/em&gt; gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As &lt;em&gt;n&lt;/em&gt; gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.&lt;/body&gt;&lt;/html&gt;</pre></div>
The other way of looking at it is to see what happens as &lt;em&gt;n&lt;/em&gt; gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As &lt;em&gt;n&lt;/em&gt; gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.&lt;/body&gt;&lt;/html&gt;</pre></div>

Revision as of 21:28, 2 September 2016

IMPORTED REVISION FROM WIKISPACES

This is an imported revision from Wikispaces. The revision metadata is included below for reference:

This revision was by author davethecomposer and made on 2016-09-02 21:28:29 UTC.
The original revision id was 590988684.
The revision comment was:

The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.

Original Wikitext content:

<span style="color: #00abda; font-family: 'Times New Roman',Times,serif; font-size: 149%;">0 Equal Divisions per Ditave (Octave)</span>

There are two ways to approach this idea.

Given that //n////-//edo means that you are dividing the octave into 1///n// equal divisions and that 1/0 is undefined in standard mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all.

The other way of looking at it is to see what happens as //n// gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As //n// gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.

Original HTML content:

<html><head><title>0edo</title></head><body><span style="color: #00abda; font-family: 'Times New Roman',Times,serif; font-size: 149%;">0 Equal Divisions per Ditave (Octave)</span><br />
<br />
There are two ways to approach this idea.<br />
<br />
Given that <em>n</em><em>-</em>edo means that you are dividing the octave into 1<em>/n</em> equal divisions and that 1/0 is undefined in standard mathematics, it would follow that 0edo would be similarly undefined and thus would comprise no sounds at all.<br />
<br />
The other way of looking at it is to see what happens as <em>n</em> gets smaller. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As <em>n</em> gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one note without any octaves.</body></html>
Retrieved from "https://en.xen.wiki/index.php?title=0edo&oldid=3962"