S-expression: Difference between revisions
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== | == S(k − 1)*Sk*S(k + 1) (1/3-square-particulars) == | ||
This section concerns commas of the form {{nowrap|S(''k'' − 1) * S''k'' * S(''k'' + 1) {{=}} {{sfrac| {{sfrac|''k'' − 1|''k'' − 2}} | {{sfrac|''k'' + 2|''k'' + 1}} }}}} which therefore do not (directly) involve the ''k''th harmonic. | This section concerns commas of the form {{nowrap|S(''k'' − 1) * S''k'' * S(''k'' + 1) {{=}} {{sfrac| {{sfrac|''k'' − 1|''k'' − 2}} | {{sfrac|''k'' + 2|''k'' + 1}} }}}} which therefore do not (directly) involve the ''k''th harmonic. | ||