Generalized superparticulars: Difference between revisions
Jump to navigation
Jump to search
Cmloegcmluin (talk | contribs) Created page with "According to Thomas Taylor's [https://books.google.com.au/books?id=VuY3AAAAMAAJ Theoretic Arithmetic, in Three Books], superparticular ratios are defined as those for which th..." |
Cmloegcmluin (talk | contribs) add categories |
||
Line 9: | Line 9: | ||
More details can be found on this forum thread here: [http://forum.sagittal.org/viewtopic.php?f=4&t=410 Generalisation of the terms "epimoric" and "superparticular" as applied to ratios] | More details can be found on this forum thread here: [http://forum.sagittal.org/viewtopic.php?f=4&t=410 Generalisation of the terms "epimoric" and "superparticular" as applied to ratios] | ||
[[Category:Terms]] | |||
[[Category:Math]] |
Revision as of 17:29, 10 December 2021
According to Thomas Taylor's Theoretic Arithmetic, in Three Books, superparticular ratios are defined as those for which the denominator divides into the numerator once, leaving a remainder of one.
In almost every case, this checks out with the popular usage of superparticular to mean ratios of the form (n+1)/n. In only one case does it deviate: that of 2/1. According to Taylor, 2/1 is not superparticular, because 1 divides into 2 twice, leaving a remainder of 0.
Taylor's book further describes generalizations of the superparticulars:
- superbiparticulars are those where the denominator divides into the numerator once, but leaves a remainder of two (such as 5/3)
- double superparticulars are those where the denominator divides into the numerator twice, leaving a remainder of one (such as 5/2)
- one can go on and on, with e.g. triple supertriparticulars where both the divisions and the remainder are 3 (such as 15/4).
More details can be found on this forum thread here: Generalisation of the terms "epimoric" and "superparticular" as applied to ratios