POTE tuning: Difference between revisions
m Cleanup and minor correction |
Improvement (see talk) |
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# Form a matrix V from M by multiplying by the diagonal matrix which is zero off the diagonal and 1/log2(p) on the diagonal; in other words the diagonal is [1 1/log2(3) 1/log2(5) 1/log2(7)]. Another way to say this is that each val is "weighted" by dividing through by the logarithms, so that V = [{{val|1 0 2/log2(5) -1/log2(7)}}, {{val|5/log2(3) 1/log2(5) 12/log2(7)}}] | # Form a matrix V from M by multiplying by the diagonal matrix which is zero off the diagonal and 1/log2(p) on the diagonal; in other words the diagonal is [1 1/log2(3) 1/log2(5) 1/log2(7)]. Another way to say this is that each val is "weighted" by dividing through by the logarithms, so that V = [{{val|1 0 2/log2(5) -1/log2(7)}}, {{val|5/log2(3) 1/log2(5) 12/log2(7)}}] | ||
# Find the matrix P = V | # Find the matrix P = V<sup>T</sup>(VV<sup>T</sup>)<sup>-1</sup>. | ||
# Find | # Find the TE = {{val|1 1 1 1}}P. | ||
# Find POTE = | # Find the TE octave: O<sub>TE</sub> = (TE*V)<sub>1</sub>, that is, the first entry of TE*V. | ||
# Find the POTE = TE/O<sub>TE</sub>; in other words TE scalar divided by O<sub>TE</sub>. | |||
If you carry out these operations, you should find | If you carry out these operations, you should find | ||
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* V ~ [{{val|1 0 0.861 -0.356}}, {{val|0 3.155 0.431 4.274}}] | * V ~ [{{val|1 0 0.861 -0.356}}, {{val|0 3.155 0.431 4.274}}] | ||
* | * TE ~ {{val|1.000902 0.317246}} | ||
* POTE ~ {{val|1 0.3169600}} | * POTE ~ {{val|1 0.3169600}} |