Equave limit: Difference between revisions

Fredg999 (talk | contribs)
Move "purpose" section to lead section, mark term as idiosyncratic, categories
ArrowHead294 (talk | contribs)
mNo edit summary
Line 2: Line 2:


==Definition==
==Definition==
The '''q-equave-n-limit''' is defined as the set of all positive rationals <big><big><math>\displaystyle
The '''q-equave-n-limit''' is defined as the set of all positive rationals <math>\displaystyle
{q^z}\cdot\frac{u}{v}
{q^z}\cdot\frac{u}{v}
</math></big></big>, where:
</math>, where:
* <math>q∈Q+</math>​ (i.e., <math>q</math> is a positive rational number), called the '''equave''',
* <math>q \in \mathbb{Q}^{+}</math>​ (i.e., <math>q</math> is a positive rational number), called the '''equave''',
* <math>z∈Z</math>​ (i.e., <math>z</math> is an integer, positive or negative),
* <math>z \in \mathbb{Z}</math>​ (i.e., <math>z</math> is an integer, positive or negative),
* <math>u,v∈Z+</math>​​ (i.e., <math>u</math> and <math>v</math> are positive integers) such that <math>u≤n</math> and <math>v≤n</math>,
* <math>u,v \in \mathbb{Z}^{+}</math>​​ (i.e., <math>u</math> and <math>v</math> are positive integers) such that <math>u \leqslant n</math> and <math>v \leqslant n</math>,
* <math>n∈Z+</math>​​ (i.e., <math>n</math> is a positive integer), called the '''limit'''.
* <math>n \in \mathbb{Z}^{+}</math>​​ (i.e., <math>n</math> is a positive integer), called the '''limit'''.


The parameter <math>n</math> places an upper bound on the values of the integers <math>u</math> and <math>v</math>, meaning that both <math>u</math> and <math>v</math> are less than or equal to <math>n</math>. Thus, the '''q-equave-n-limit''' consists of ratios generated by multiplying a power of <math>q</math> by ratios <math>\displaystyle
The parameter <math>n</math> places an upper bound on the values of the integers <math>u</math> and <math>v</math>, meaning that both <math>u</math> and <math>v</math> are less than or equal to <math>n</math>. Thus, the '''q-equave-n-limit''' consists of ratios generated by multiplying a power of <math>q</math> by ratios <math>\displaystyle