Just intonation subgroup/Mike's tips: Difference between revisions

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On Thu, Nov 1, 2012 at 9:10 PM, Chris Vaisvil <[email protected]>
== Mike's tips ==
<pre>
On Thu, Nov 1, 2012 at 9:10 PM, Chris Vaisvil <[email protected]> wrote:


wrote:
> For certain, no. I could only guess that subgroups are actually harmonic series prime limits.
<br>&gt;
<br>&gt; For certain, no. I could only guess that subgroups are actually harmonic
<br>&gt; series prime limits.


Subgroups expand the concept of a prime limit. For instance, say you
Subgroups expand the concept of a prime limit. For instance, say you want the 7-limit, but you don't care about prime 5; you just want primes 2, 3, and 7. So that's the 2.3.7 subgroup. Or say that you want the 7-limit, but you don't care about 3/1 but you do care about 9/1. Then that's the 2.5.7.9 subgroup. Or, say that you want primes 2 and 3, and the composite interval 7/5; that's the 2.3.7/5 subgroup. The rule for any subgroup is that if you multiply or divide intervals, that's also in the subgroup. So for the 2.3.7 subgroup, 7*3 = 21/1 is in the subgroup, as is 7/(2*3) = 7/6. And for the 2.3.7/5 subgroup, 2/(7/5 * 7/5) = 50/49 is in the subgroup, and so on. They're infinite lattices of intervals.
 
want the 7-limit, but you don't care about prime 5; you just want
 
primes 2, 3, and 7. So that's the 2.3.7 subgroup. Or say that you want
 
the 7-limit, but you don't care about 3/1 but you do care about 9/1.
 
Then that's the 2.5.7.9 subgroup. Or, say that you want primes 2 and
 
3, and the composite interval 7/5; that's the 2.3.7/5 subgroup.
 
The rule for any subgroup is that if you multiply or divide intervals,
 
that's also in the subgroup. So for the 2.3.7 subgroup, 7*3 = 21/1 is
 
in the subgroup, as is 7/(2*3) = 7/6. And for the 2.3.7/5 subgroup,
 
2/(7/5 * 7/5) = 50/49 is in the subgroup, and so on. They're infinite
 
lattices of intervals.


11-EDO happens to be a decent temperament for the 2.7.9.11 subgroup.
11-EDO happens to be a decent temperament for the 2.7.9.11 subgroup.
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-Mike
-Mike


Anyway, you asked about figuring out what steps in 11-EDO approximate
Anyway, you asked about figuring out what steps in 11-EDO approximate what intervals. So if 11-EDO supports the 2.7.9.11 subgroup, I can just give you the mappings for 2/1, 7/1, 9/1, and 11/1, and you can mix and match them to get what intervals you want, right. So for instance, 2/1 is 11 steps, 7/1 is 31 steps, 9/1 is 35 steps, and 11/1 is 38 steps. So then 11/9 is 38-35 = 3 steps. That should be enough information for you to get all the intervals.
 
what intervals. So if 11-EDO supports the 2.7.9.11 subgroup, I can
 
just give you the mappings for 2/1, 7/1, 9/1, and 11/1, and you can
 
mix and match them to get what intervals you want, right. So for
 
instance, 2/1 is 11 steps, 7/1 is 31 steps, 9/1 is 35 steps, and 11/1
 
is 38 steps. So then 11/9 is 38-35 = 3 steps. That should be enough
 
information for you to get all the intervals.


-Mike
-Mike


OK, so rather than write all of that out in English, though, we can
OK, so rather than write all of that out in English, though, we can just use a simple notation. So if 2/1 is 11 steps, 7/1 is 31 steps, 9/1 is 35 steps, and 11/1 is 38 steps, then we can just condense all that as follows:


just use a simple notation. So if 2/1 is 11 steps, 7/1 is 31 steps,
<11 31 35 38|


9/1 is 35 steps, and 11/1 is 38 steps, then we can just condense all
where it's understood in this particular case that the coefficients represent how many steps map to 2/1, 7/1, 9/1 and 11/1, respectively. This is called a val, and this is why we use them; so we can figure out how many steps every interval maps to. So 9/7 in the above case is 35-31 = 4 steps.


that as follows:
-Mike</pre>


&lt;11 31 35 38|
== Jake's tips ==
 
<pre>
where it's understood in this particular case that the coefficients
Chris Vaisvil said:
 
represent how many steps map to 2/1, 7/1, 9/1 and 11/1, respectively.
 
This is called a val, and this is why we use them; so we can figure
 
out how many steps every interval maps to. So 9/7 in the above case is
 
35-31 = 4 steps.
 
-Mike


Chris Vaisvil said:
> As someone pretty ignorant of tuning theory I wish there was a table that said


<br>&gt; As someone pretty ignorant of tuning theory I wish there was a table that said
> If you play scale (tuning) steps 0:4:8:10 in 11 edo you will come close to approximating a harmonic series chord of 0:3:6:7
<br>&gt;
<br>&gt; If you play scale (tuning) steps 0:4:8:10 in 11 edo you will come close to
<br>&gt; approximating a harmonic series chord of 0:3:6:7


There's an easy way to do that in Scala.  
There's an easy way to do that in Scala.  
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Jake
Jake
</pre>