User:FloraC/Fokker analysis of rank-3 scales: Difference between revisions
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<math>\displaystyle C_\text{r} = 135/128, C_\text{d} = 81/80</math> | <math>\displaystyle C_\text{r} = 135/128, C_\text{d} = 81/80</math> | ||
It is the same as | It is the same as bilawal. Therefore, we find | ||
<math>\displaystyle L = 9/8, l = 10/9, S = 16/15, s = 256/243</math> | <math>\displaystyle L = 9/8, l = 10/9, S = 16/15, s = 256/243</math> | ||
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However, the step size relations do not satisfy the property of rank-3 Fokker blocks. Specifically, the 3-steps are 729/640, 6/5, 5/4 and 320/243, and we have (6/5)/(729/640) = (320/243)/(5/4). Therefore, we find the chromas ''C''<sub>r</sub> = 800/729 and ''C''<sub>d</sub> = 256/243. In the 5-steps, they are 27/20, 45/32, 64/45, 40/27. This corresponds to a different set of chromas: ''C''<sub>r</sub> = 256/243 and ''C''<sub>d</sub> = 25/24. No Fokker block has different | However, the step size relations do not satisfy the property of rank-3 Fokker blocks. Specifically, the 3-steps are 729/640, 6/5, 5/4 and 320/243, and we have (6/5)/(729/640) = (320/243)/(5/4). Therefore, we find the chromas ''C''<sub>r</sub> = 800/729 and ''C''<sub>d</sub> = 256/243. In the 5-steps, they are 27/20, 45/32, 64/45, 40/27. This corresponds to a different set of chromas: ''C''<sub>r</sub> = 256/243 and ''C''<sub>d</sub> = 25/24. No Fokker block has different sets of chromas. | ||
Indeed, blackdye cannot be decomposed into the product word of two mosses. | Indeed, blackdye cannot be decomposed into the product word of two mosses. | ||