User:FloraC/Fokker analysis of rank-3 scales: Difference between revisions

Modal chroma > residual chroma, redefine residual stability accordingly
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Fokker analysis refers to the analysis of scales as Fokker blocks. In this essay, Fokker analysis of rank-3 scales is illustrated and the related issues are discussed in later chapters.  
Fokker analysis refers to the analysis of scales as Fokker blocks. In this essay, Fokker analysis of rank-3 scales is illustrated and the related issues are discussed in later chapters.  


Rank-1 scales i.e. equal-step scales and rank-2 scales i.e. mos scales have been well explored. The scene of rank-3 scales has been a mess. Fragmented definitions and theories are all over the place. It will benefit from Fokker analysis very prominently.  
Rank-1 scales i.e. equal-step scales and rank-2 scales i.e. mos scales have been well explored. The scene of rank-3 scales has been a mess. Fragmented definitions and theories are all over the place. So it will benefit from Fokker analysis very prominently.  


== Notation ==
== Notation ==
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Two chromas are to be named: the residual chroma
Two chromas are to be named: the residual chroma


<math>\displaystyle C_r = L - S = l - s</math>
<math>\displaystyle C_\text{r} = L - S = l - s</math>


and the domal chroma  
and the domal chroma  


<math>\displaystyle C_d = L - l = S - s</math>
<math>\displaystyle C_\text{d} = L - l = S - s</math>


These form the chroma basis {''C''<sub>r</sub>, ''C''<sub>d</sub>} of the rank-3 Fokker block. The residual chroma is assumed to be always larger than the domal chroma – since the chroma basis is essentially orderless, no Fokker block is missed or duplicate by the assumption.  
These form the chroma basis {''C''<sub>r</sub>, ''C''<sub>d</sub>} of the rank-3 Fokker block. The residual chroma is assumed to be always larger than the domal chroma – since the chroma basis is essentially orderless, no Fokker block is missed or duplicate by the assumption.  
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<math>\displaystyle
<math>\displaystyle
C_r + C_d = L - s \\
C_\text{r} + C_\text{d} = L - s \\
C_r - C_d = l - S
C_\text{r} - C_\text{d} = l - S
</math>
</math>


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<math>\displaystyle
<math>\displaystyle
C_1 = C_r + C_d \\
C_1 = C_\text{r} + C_\text{d} \\
C_2 = C_r \\
C_2 = C_\text{r} \\
C_3 = C_r - C_d \\
C_3 = C_\text{r} - C_\text{d} \\
C_4 = C_d
C_4 = C_\text{d}
</math>
</math>


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The 2-step clearly shows us that the four chromas involved are 2187/2048, 135/128, 25/24 and 81/80, so we find
The 2-step clearly shows us that the four chromas involved are 2187/2048, 135/128, 25/24 and 81/80, so we find


<math>\displaystyle C_r = 135/128, C_d = 81/80</math>
<math>\displaystyle C_\text{r} = 135/128, C_\text{d} = 81/80</math>


Therefore, we find
Therefore, we find
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First we may assume
First we may assume


<math>\displaystyle C_r = 135/128, C_d = 81/80</math>
<math>\displaystyle C_\text{r} = 135/128, C_\text{d} = 81/80</math>


It is the same as Aura's diatonic scale. Therefore, we find
It is the same as Aura's diatonic scale. Therefore, we find
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; Fokker block 2
; Fokker block 2


<math>\displaystyle C_r = 25/24, C_d = 81/80</math>
<math>\displaystyle C_\text{r} = 25/24, C_\text{d} = 81/80</math>


Therefore, we find
Therefore, we find
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; Fokker block 3
; Fokker block 3


<math>\displaystyle C_r = 135/128, C_d = 25/24</math>
<math>\displaystyle C_\text{r} = 135/128, C_\text{d} = 25/24</math>


Therefore, we find
Therefore, we find
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The different part is that still four distinct chromas are involved. They are 7168/6561, 784/729, 343/324, 64/63. The set defines a unique chroma basis. It is
The different part is that still four distinct chromas are involved. They are 7168/6561, 784/729, 343/324, 64/63. The set defines a unique chroma basis. It is


<math>\displaystyle C_r = 784/729, C_d = 64/63</math>
<math>\displaystyle C_\text{r} = 784/729, C_\text{d} = 64/63</math>


Therefore, we find
Therefore, we find