EFD: Difference between revisions

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An '''EFD''', or '''equal frequency division''', is a kind of [[Arithmetic tunings|arithmetic]] and [[Harmonotonic tunings|harmonotonic]] tuning.
An '''EFD''' ('''equal frequency division''') or '''AD''' ('''arithmetic division''') is a [[period]]ic and [[Arithmetic tuning|arithmetic]] [[tuning system]] in which each period is divided to a number of steps of equal frequency difference.  


== Specification ==
== Specification ==


Its full specification is n-EFDp: n equal frequency divisions of irrational interval p.  
Its full specification is ''n''-efd-''p'' or ''n''-ad-''p'': ''n'' equal frequency divisions of ''p'', or ''n'' arithmetic divisions of ''p'' .  


== Formula ==
== Formula ==


To find the steps for an n-EFDp, begin by recognizing that while the multiplicative interval relating your root position to the end position is <span><math>p</math></span> (or <span><math>\frac p1</math></span>), if you are going to move arithmetically (by repeated addition) from <span><math>1</math></span> to <span><math>p</math></span>, then the difference in frequency space that you are dividing up is not actually <span><math>p</math></span>, but <span><math>p - 1</math></span>. And because you are dividing it into <span><math>n</math></span> parts, each step will have a size of <span><math>\frac{p-1}{n}</math></span>. So, the formula for the frequency of step <span><math>k</math></span> of an n-EFDp is:
To find the steps for an ''n''-efd-''p'', begin by recognizing that while the multiplicative interval relating your root position to the end position is <math>p</math> (or <math>\frac p1</math>), if you are going to move arithmetically (by repeated addition) from <math>1</math> to <math>p</math>, then the difference in frequency space that you are dividing up is not actually <math>p</math>, but <math>p - 1</math>. And because you are dividing it into <math>n</math> parts, each step will have a size of <math>\frac{p-1}{n}</math>. So within each period, the ratio ''c'' of the ''k''-th step of an ''n''-efd-''p'' is:


<math>
<math>
f(k) = 1 + (\frac kn)(p-1)
c = 1 + (\frac kn)(p-1)
</math>
</math>


This way, when <span><math>k</math></span> is <span><math>0</math></span>, <span><math>f(k)</math></span> is simply <span><math>1</math></span>. And when <span><math>k</math></span> is <span><math>n</math></span>, <span><math>f(k)</math></span> is simply <span><math>1 + (p-1) = p</math></span>.  
This way, when <math>k</math> is <math>0</math>, <math>f(k)</math> is simply <math>1</math>. And when <math>k</math> is <math>n</math>, <math>f(k)</math> is simply <math>1 + (p-1) = p</math>.  


== Relationship to other tunings  ==
== Relationship to other tunings  ==
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