S-expression: Difference between revisions

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 <math>\displaystyle S(k-1) * Sk * S(k+1) = \frac{9n^2 - 1}{9n^2 - 4}</math>
-In other words, what this shows is all {{frac|1|3}}-square-particulars of the form {{frac|S(''k'' − 1) * S''k'' * S(''k'' + 1)}} are superparticular iff ''k'' is throdd (not a multiple of 3), and all {{frac|1|3}}-square-particulars of the form {{nowrap|S(3''k'' − 1) * S(3''k'') * S(3''k'' + 1)}} are throdd-particular with the numerator and denominator always being one less than a multiple of 3 (which is to say, commas of this form are throdd-particular iff ''k'' is threven and superparticular iff ''k'' is throdd).
+In other words, what this shows is all {{frac|1|3}}-square-particulars of the form S(''k'' − 1) * S''k'' * S(''k'' + 1) are superparticular iff ''k'' is throdd (not a multiple of 3), and all {{frac|1|3}}-square-particulars of the form {{nowrap|S(3''k'' − 1) * S(3''k'') * S(3''k'' + 1)}} are throdd-particular with the numerator and denominator always being one less than a multiple of 3 (which is to say, commas of this form are throdd-particular iff ''k'' is threven and superparticular iff ''k'' is throdd).
 === Tables of 1/n-square-particulars ===