Fraenkel word: Difference between revisions

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To prove this, we prove the following lemmas by induction on ''n'':
To prove this, we prove the following lemmas by induction on ''n'':


{{theorem|name=Lemma|contents=Let ''G''<sub>''n''</sub> denote the non-circular Fraenkel word on ''n'' letters. For all ''n'' &ge; 1, 0 &le; ''i'' &le; ''n'' &minus; 1, and 1 &le; {{!}}''w''{{!}} &le; 2<sup>''n''/2</sup> &minus; 2, the following holds for any length-{{!}}''w''{{!}} subword ''w'' of ''G''<sub>''n''</sub>:
{{theorem|name=Lemma|contents=Let ''G''<sub>''n''</sub> denote the non-circular Fraenkel word on ''n'' letters. For all ''n'' &ge; 1, 0 &le; ''i'' &le; ''n'' &minus; 1, and 1 &le; {{!}}''w''{{!}} &le; 2<sup>''n''/2</sup> &minus; 2, the following holds for any subword ''w'' of ''G''<sub>''n''</sub>:
# If {{!}}''w''{{!}} ≡ 0 mod 2<sup>''i''+1</sup>, then {{!}}''w''{{!}}<sub>'''i'''</sub> = {{!}}''w''{{!}}/2<sup>''i''+1</sup>
# If {{!}}''w''{{!}} ≡ 0 mod 2<sup>''i''+1</sup>, then {{!}}''w''{{!}}<sub>'''i'''</sub> = {{!}}''w''{{!}}/2<sup>''i''+1</sup>
# If {{!}}''w''{{!}} ≢ 0 mod 2<sup>''i''+1</sup>, then {{!}}''w''{{!}}<sub>'''i'''</sub> = either floor({{!}}''w''{{!}}/2<sup>''i''+1</sup>) or ceil({{!}}''w''{{!}}/2<sup>''i''+1</sup>).
# If {{!}}''w''{{!}} ≢ 0 mod 2<sup>''i''+1</sup>, then {{!}}''w''{{!}}<sub>'''i'''</sub> = either floor({{!}}''w''{{!}}/2<sup>''i''+1</sup>) or ceil({{!}}''w''{{!}}/2<sup>''i''+1</sup>).