User:PiotrGrochowski/User:PiotrGrochowski: Difference between revisions

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<div><big>''He did nothing wrong''</big></div>
<div><big>''He did nothing wrong''</big></div>


Edos are for calculating approximate logarithms in mathematics. The right choice of an edo (such as [[53edo]] or even [[612edo]] for 5-limit numbers) would give accurate results.</span>
Edos are for calculating approximate logarithms in mathematics. The right choice of an edo (such as [[53edo]] or even [[612edo]] for 5-limit numbers) would give accurate results.
 
<pre>Which number is the biggest?
A. 81^56
B. 9^100
C. 27^72
D. 2^224</pre>
 
53log₂(81^56)≈18816<br>
53log₂(9^100)≈16800<br>
53log₂(27^72)≈18144<br>
53log₂(2^224)=11872
 
<b>A.</b>
 
(calculated successfully with [[53edo]])
 
<pre>³√(2 7/9)÷³√(3/5) rounded to the nearest integer is
A. 1
B. 2
C. 3
D. 4</pre>
 
53log₂(³√(25/9)÷³√(3/5))≈39
 
2^(39÷53)≈5÷3
 
round(5÷3)=2
 
<b>B.</b>
 
(calculated successfully with [[53edo]])
 
<pre>Which number is the smallest?
A. 5√3
B. 4√7
C. 8√2
D. 3√11</pre>
 
41log₂(5√3)≈127.5<br>
41log₂(4√7)≈139.5<br>
41log₂(8√2)=143.5<br>
41log₂(3√11)≈136
 
<b>A.</b>
 
(calculated successfully with [[41edo]])
 
</span>


<!--For information about me, see [[Editor PiotrGrochowski]]
<!--For information about me, see [[Editor PiotrGrochowski]]

Latest revision as of 04:07, 9 April 2025

Do not ban this user
He did nothing wrong

Edos are for calculating approximate logarithms in mathematics. The right choice of an edo (such as 53edo or even 612edo for 5-limit numbers) would give accurate results.

Which number is the biggest?
A. 81^56
B. 9^100
C. 27^72
D. 2^224

53log₂(81^56)≈18816
53log₂(9^100)≈16800
53log₂(27^72)≈18144
53log₂(2^224)=11872

A.

(calculated successfully with 53edo)

³√(2 7/9)÷³√(3/5) rounded to the nearest integer is
A. 1
B. 2
C. 3
D. 4

53log₂(³√(25/9)÷³√(3/5))≈39

2^(39÷53)≈5÷3

round(5÷3)=2

B.

(calculated successfully with 53edo)

Which number is the smallest?
A. 5√3
B. 4√7
C. 8√2
D. 3√11

41log₂(5√3)≈127.5
41log₂(4√7)≈139.5
41log₂(8√2)=143.5
41log₂(3√11)≈136

A.

(calculated successfully with 41edo)