Binary logarithm
IMPORTED REVISION FROM WIKISPACES
This is an imported revision from Wikispaces. The revision metadata is included below for reference:
- This revision was by author xenwolf and made on 2011-06-13 05:20:31 UTC.
- The original revision id was 236184758.
- The revision comment was:
The revision contents are below, presented both in the original Wikispaces Wikitext format, and in HTML exactly as Wikispaces rendered it.
Original Wikitext content:
The symbol **log2** is often used for the **[[http://en.wikipedia.org/wiki/Binary_logarithm|binary logarithm]]**, also called //dual logarithm//. == Log2 of the first primes == ||~ prime ||~ log2 prime || || 2 || 1 || || 3 || 1.584962501 || || 5 || 2.321928095 || || 7 || 2.807354922 || || 11 || 3.459431619 || || 13 || 3.700439718 || || 17 || 4.087462841 || || 19 || 4.247927513 || || 23 || 4.523561956 || || 29 || 4.857980995 || You can calculate the binary logarithm of n like this log2(n) = ln(n)/ln(2)
Original HTML content:
<html><head><title>log2</title></head><body>The symbol <strong>log2</strong> is often used for the <strong><a class="wiki_link_ext" href="http://en.wikipedia.org/wiki/Binary_logarithm" rel="nofollow">binary logarithm</a></strong>, also called <em>dual logarithm</em>.<br />
<br />
<!-- ws:start:WikiTextHeadingRule:0:<h2> --><h2 id="toc0"><a name="x-Log2 of the first primes"></a><!-- ws:end:WikiTextHeadingRule:0 --> Log2 of the first primes </h2>
<table class="wiki_table">
<tr>
<th>prime<br />
</th>
<th>log2 prime<br />
</th>
</tr>
<tr>
<td>2<br />
</td>
<td>1<br />
</td>
</tr>
<tr>
<td>3<br />
</td>
<td>1.584962501<br />
</td>
</tr>
<tr>
<td>5<br />
</td>
<td>2.321928095<br />
</td>
</tr>
<tr>
<td>7<br />
</td>
<td>2.807354922<br />
</td>
</tr>
<tr>
<td>11<br />
</td>
<td>3.459431619<br />
</td>
</tr>
<tr>
<td>13<br />
</td>
<td>3.700439718<br />
</td>
</tr>
<tr>
<td>17<br />
</td>
<td>4.087462841<br />
</td>
</tr>
<tr>
<td>19<br />
</td>
<td>4.247927513<br />
</td>
</tr>
<tr>
<td>23<br />
</td>
<td>4.523561956<br />
</td>
</tr>
<tr>
<td>29<br />
</td>
<td>4.857980995<br />
</td>
</tr>
</table>
<br />
You can calculate the binary logarithm of n like this<br />
<br />
log2(n) = ln(n)/ln(2)</body></html>