S-expression: Difference between revisions
m →Mathematical derivation: seemed unnecessarily precise/formal |
m →Sk/S(k+1) (ultraparticulars): trying to fix redirect to appropriate section |
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((3k+3)/(3k))/((3k+2)/(3k+1))<sup>3</sup> = (k+1)/k / ((3k+2)/(3k+1))<sup>3</sup> | ((3k+3)/(3k))/((3k+2)/(3k+1))<sup>3</sup> = (k+1)/k / ((3k+2)/(3k+1))<sup>3</sup> | ||
Also note that if you temper multiple adjacent ultraparticulars, you sometimes aren't required to use those ultraparticulars in the comma list due to an interesting case of [[Sk/S(k+2)]], discussed next. | Also note that if you temper multiple adjacent ultraparticulars, you sometimes aren't required to use those ultraparticulars in the comma list due to an interesting case of [[#Sk/S(k+2) (semiparticulars)]], discussed next. | ||
== Sk/S(k+2) (semiparticulars) == | == Sk/S(k+2) (semiparticulars) == | ||