Ternary scale theorems: Difference between revisions

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 # '''x''' + '''y'''
 # '''x''' + '''z'''
-We also know that ''s'' is of the form ''w''('''x''', '''y''', '''z''')''w''('''x''', '''z''', '''y'''). Hence the count of '''x''' + '''y''' = the count of '''x''' + '''z''', counting all 2-steps in all of ''s''.
+We also know that ''s'' is of the form ''w''('''x''', '''y''', '''z''')''w''('''x''', '''z''', '''y'''). Hence the number of occurrences of '''x''' + '''y''' = the number of occurrences of '''x''' + '''z''', counting all 2-steps in all of ''s''.
 Write ''s''<sub>1</sub> for the scale word made from stacked 2-steps from the 0-degree, and let ''s''<sub>2</sub> be the scale word of stacked 2-steps from the 1-degree.