Hodge dual: Difference between revisions
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So we find <math>\star(v_1 \wedge v_2) = 4e_1 - 4e_2 + e_3</math>, which matches with what we expect from above, up to sign. | So we find <math>\star(v_1 \wedge v_2) = 4e_1 - 4e_2 + e_3</math> (which is the monzo for the descending syntonic comma), which matches with what we expect from above, up to sign. | ||
The Hodge dual \( \star(v_1 \wedge v_2) \) directly gives the generator of <math> \ker M </math>. | The Hodge dual \( \star(v_1 \wedge v_2) \) directly gives the generator of <math> \ker M </math>. | ||