Single-pitch tuning: Difference between revisions
Created page with "Single-pitch tuning refers to any tuning system that contains only a single note: all notes are represented by the same note; this is different from 1edo because not even..." |
mNo edit summary |
||
Line 5: | Line 5: | ||
'''0 equal divisions of the octave''' ('''0edo''') (or 0ed-''p'' for any interval ''p'') is an interpretation of single-pitch tuning as an EDO. | '''0 equal divisions of the octave''' ('''0edo''') (or 0ed-''p'' for any interval ''p'') is an interpretation of single-pitch tuning as an EDO. | ||
The way to approach the idea of 0edo that leads to single-pitch tuning is to see what happens as ''n'' gets smaller in ''n''-edo. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As ''n'' gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one pitch without any octaves. | The way to approach the idea of 0edo that leads to single-pitch tuning is to see what happens as ''n'' gets smaller in ''n''-edo. At 1-edo you have one note per octave. At 0.5-edo you have 1/0.5 which is one note every two octaves. As ''n'' gets smaller you reach a point where you only have one note within an audible octave range and any other notes outside of this range. Taking this to its conclusion, and assuming you want 0edo to be defined, you would conclude that 0edo is just one pitch without any octaves, which is, arguably, pure rhythm. | ||
An alternative interpretation is that given that ''n''-edo means that you are dividing the octave into equal divisions with a logarithmic size of 1/n octaves, and that [[1/0]] is sometimes considered undefined, it would follow that 0edo would be similarly undefined and thus one could not use it as a tuning system. | An alternative interpretation is that given that ''n''-edo means that you are dividing the octave into equal divisions with a logarithmic size of 1/n octaves, and that [[1/0]] is sometimes considered undefined, it would follow that 0edo would be similarly undefined and thus one could not use it as a tuning system. |