Neutral and interordinal intervals in MOS scales: Difference between revisions

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* To show that these actually occur in bL(a &minus; b)s, consider smaller and larger j-steps (1 ≤ j ≤ a &minus; 1) in the parent mos. These intervals also occur in the mos aLbs separated by s, and the number of j’s (“junctures”) that correspond to these places in aLbs is exactly a &minus; 1. These j's correspond to values of k such that larger k-step < smaller (k + 1)-step. Note that we are considering “junctures” between k-steps and (k + 1)-steps in aLbs, excluding k = 0 and k = a + b &minus; 1, so the total number of “junctures” to consider is finite, namely a + b &minus; 2. This proves parts (1) and (2).
* To show that these actually occur in bL(a &minus; b)s, consider smaller and larger j-steps (1 ≤ j ≤ a &minus; 1) in the parent mos. These intervals also occur in the mos aLbs separated by s, and the number of j’s (“junctures”) that correspond to these places in aLbs is exactly a &minus; 1. These j's correspond to values of k such that larger k-step < smaller (k + 1)-step. Note that we are considering “junctures” between k-steps and (k + 1)-steps in aLbs, excluding k = 0 and k = a + b &minus; 1, so the total number of “junctures” to consider is finite, namely a + b &minus; 2. This proves parts (1) and (2).


Part (3) is also immediate now: when larger k-step = smaller (k + 1)-step, larger (k + 1)-step &minus; smaller k-step = 2(L &minus; s) = 2s = L. The step L is 4 steps in 2n-edo.
Part (3) is also immediate now: when larger k-step = smaller (k + 1)-step, larger (k + 1)-step &minus; smaller k-step = 2(L &minus; s) = 2s = L. The step L is 4 steps in 2n-edo. {{qed}}


=== Corollary ===
=== Corollary ===