Neutral and interordinal intervals in MOS scales: Difference between revisions
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Tags: Mobile edit Mobile web edit |
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*** <pre>Y=L^A sL...LsL...LsL...LsL...LsL^B</pre> | *** <pre>Y=L^A sL...LsL...LsL...LsL...LsL^B</pre> | ||
*** <pre>X=L^CsL...LsL...LsL^D</pre> | *** <pre>X=L^CsL...LsL...LsL^D</pre> | ||
** Let r be the number of complete chunks (maximal contiguous strings of L's) in X, and let μ = n/(a+b). We'll obtain a contradiction. By the Discretizing Lemma, we have (|•| denotes length): | ** Let r be the number of complete chunks (maximal contiguous strings of L's) in X, and let μ = n/(a+b). Note that since a > b, 3/2 < μ < 2. We'll obtain a contradiction. | ||
** By the Discretizing Lemma, we have (|•| denotes length): | |||
*** 1+A+B+floor((r+2)μ) <= |Y| <= 1+A+B+ceil((r+2)μ) | *** 1+A+B+floor((r+2)μ) <= |Y| <= 1+A+B+ceil((r+2)μ) | ||
*** 1+C+D+floor(rμ) <= |X| <= 1+C+D+ceil(rμ) | *** 1+C+D+floor(rμ) <= |X| <= 1+C+D+ceil(rμ) |