Temperament merging: Difference between revisions

Cmloegcmluin (talk | contribs)
temper out → vanish
Cmloegcmluin (talk | contribs)
Grade-deficiencies: fixes and clarifications
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\end{array} \right]
\end{array} \right]


\text{which in normal form is}
\text{which in canonical form* is}


\left[ \begin{array} {r|r|r|r}
\left[ \begin{array} {r|r|r|r}


\colorbox{pink}0 & -24 & -5 & -23 \\
\colorbox{pink}0 & -49 & -45 & -36 \\
\colorbox{pink}0 & 29 & 4 & 26 \\
\colorbox{pink}0 & 31 & 27 & 21 \\
\colorbox{pink}0 & 0 & 3 & 2 \\
\colorbox{pink}0 & 0 & 1 & 0 \\
\colorbox{pink}0 & 0 & 0 & 1 \\
\colorbox{pink}0 & 0 & 0 & 1 \\


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Note that we've only put it into [[Hermite normal form]]; we've done this to illustrate that one of the vectors is now entirely zeros (highlighted in red). This means that the matrix was nullity-deficient, or in layperson's terms, contained redundant commas. In other words, these two temperaments make some of the same commas vanish, and so when we merged them, even though the input temperaments required 2 vectors each to represent, their merged result doesn't require all 4 vectors; it can be completely represented using only 3.
We haven't ''completely'' canonicalized yet; we didn't remove the all-zero column (highlighted in red) that was created by the [[Hermite normal form]] step. The existence of any all-zero columns like this tells us that our matrix was nullity-deficient, or in layperson's terms, that it contained redundant commas. In other words, these two temperaments make some of the same commas vanish, and so when we merged them — even though the input temperaments required 2 vectors each to represent — their merged result doesn't require all 4 vectors; it can be completely represented using only 3 vectors. So once we fully [[canonical form|canonicalize]], any all-zero column(s) are removed, and we end up with:
 
Once we fully [[canonical form|canonicalize]], though, the all-zero row(s) are removed, and we end up with: