Recursive structure of MOS scales: Difference between revisions

Inthar (talk | contribs)
Inthar (talk | contribs)
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Case 1.1:
Case 1.1:
  w2: <L ... sXL ... sXL ... sXL ... sXL ...L] (complete chunks followed by one or more L's)
  w₂: <L ... sXL ... sXL ... sXL ... sXL ...L] (complete chunks followed by one or more L's)
  w3:        <L ... sXL ... sXL ... sXL ... s> (complete chunks only)
  w₃:        <L ... sXL ... sXL ... sXL ... s> (complete chunks only)


This implies that the last chunk is bigger than the first one, a contradiction because w₂ begins in λ.  
This implies that the last chunk is bigger than the first one, a contradiction because w₂ begins in λ.  


Case 1.2:
Case 1.2:
  w1:  s[something with k s's]
  w₁:  s[something with k s's]
  w2: <L ... sXL ... sXL ... sXL ... s>  (complete chunks only)
  w₂: <L ... sXL ... sXL ... sXL ... s>  (complete chunks only)
  w3:        <L ... sXL ... sXL ... sXL ... s> (complete chunks only)
  w₃:        <L ... sXL ... sXL ... sXL ... s> (complete chunks only)


So W₂(L<sup>r+1</sup>s, L<sup>r</sup>s) has k+1 chunks, a contradiction.
So W₂(L<sup>r+1</sup>s, L<sup>r</sup>s) has k+1 chunks, a contradiction.
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Case 1.3:
Case 1.3:
  w2: <L ... sXL ... sXL ... sXL ... sXL ...L] (complete chunks followed by one or more L's)
  w₂: <L ... sXL ... sXL ... sXL ... sXL ...L] (complete chunks followed by one or more L's)
  w3:  [... sXL ... sXL ... sXL ... sXL ... s> (one or more L's followed by an s, followed by complete chunks)
  w₃:  [... sXL ... sXL ... sXL ... sXL ... s> (one or more L's followed by an s, followed by complete chunks)


or
or


Case 1.4:
Case 1.4:
  w2: <L ... sXL ... sXL ... sXL ... s> (complete chunks only)
  w₂: <L ... sXL ... sXL ... sXL ... s> (complete chunks only)
  w3:  [... sXL ... sXL ... sXL ... sXL ... s> (one or more L's followed by an s, followed by complete chunks)
  w₃:  [... sXL ... sXL ... sXL ... sXL ... s> (one or more L's followed by an s, followed by complete chunks)


(both 1.3 and 1.4 imply w₃ has one more s than w₂).
(both 1.3 and 1.4 imply w₃ has one more s than w₂).