Recursive structure of MOS scales: Difference between revisions

Inthar (talk | contribs)
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Inthar (talk | contribs)
Preservation of the MOS property: Added the missing case
Tags: Mobile edit Mobile web edit
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If w₂ and w₃ (which have the same length) contain the same number of complete chunks, one case is (X denotes a chunk boundary, < > are chunk boundaries that are also the boundary of the word, [] are non-chunk-boundary word boundaries.)
If w₂ and w₃ (which have the same length) contain the same number of complete chunks, one case is (X denotes a chunk boundary, < > are chunk boundaries that are also the boundary of the word, [] are non-chunk-boundary word boundaries.)


Case 1.1:
  w2: <L ... sXL ... sXL ... sXL ... sXL ...]
  w2: <L ... sXL ... sXL ... sXL ... sXL ...]
  w3:        <L ... sXL ... sXL ... sXL ... s>
  w3:        <L ... sXL ... sXL ... sXL ... s>
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This implies that the last chunk is bigger than the first one, a contradiction because w₂ begins in λ.  
This implies that the last chunk is bigger than the first one, a contradiction because w₂ begins in λ.  


In the case
Case 1.2:
  w1:  s[something with k s's]
  w1:  s[something with k s's]
  w2: <L ... sXL ... sXL ... sXL ... s>
  w2: <L ... sXL ... sXL ... sXL ... s>
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So we must have  
So we must have  


Case 1.3:
  w2: <L ... sXL ... sXL ... sXL ... sXL ...]
  w2: <L ... sXL ... sXL ... sXL ... sXL ...]
  w3:  [... sXL ... sXL ... sXL ... sXL ... s>
  w3:  [... sXL ... sXL ... sXL ... sXL ... s>
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or
or


Case 1.4:
  w2: <L ... sXL ... sXL ... sXL ... sX]
  w2: <L ... sXL ... sXL ... sXL ... sX]
  w3:  [... sXL ... sXL ... sXL ... sXL ... L s>
  w3:  [... sXL ... sXL ... sXL ... sXL ... s>


(⇒ w₃ has one more s).
(⇒ w₃ has one more s).
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If w₂ has more complete chunks than w₃: the only case to consider is when w₂ has one more chunk.  
If w₂ has more complete chunks than w₃: the only case to consider is when w₂ has one more chunk.  


  w2: <L ... sXL ... sXL ... sXL ... sXL ... sX(L ...)
Case 2.1:
  w2: <L ... sXL ... sXL ... sXL ... sXL ... s>
  w3:                <L ... sXL ... sXL ... sXL ... s>
  w3:                <L ... sXL ... sXL ... sXL ... s>
⇒ w₂ has more s's.
⇒ w₂ has more s's.


The following two cases remain:
Case 2.2:
w2: <L ... sXL ... sXL ... sXL ... sXL ... s>
w3:              [sXL ... sXL ... sXL ... sXL ... s>
⇒ do the same trick as in
 
Case 2.3:
  w2: <L ... sXL ... sXL ... sXL ... sXL ... sXL ...]
  w2: <L ... sXL ... sXL ... sXL ... sXL ... sXL ...]
  w3:          [ ... sXL ... sXL ... sXL ... sXL ... s>
  w3:          [ ... sXL ... sXL ... sXL ... sXL ... s>


Case 2.4:
  w2: <L ... sXL ... sXL ... sXL ... sXL ... sXL ...]
  w2: <L ... sXL ... sXL ... sXL ... sXL ... sXL ...]
  w3:                <L ... sXL ... sXL ... sXL ... s>
  w3:                <L ... sXL ... sXL ... sXL ... s>


Both are contradictions since the first chunk is λ so has to at least as big as the last one.
Both 2.3 and 2.4 are contradictions since the first chunk is λ so has to at least as big as the last one.


=== Preservation of generators ===
=== Preservation of generators ===