Recursive structure of MOS scales: Difference between revisions

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# w₃(L, s) = the last K+1 letters of W₂(L<sup>r+1</sup>s, L<sup>r</sup>s)
# w₃(L, s) = the last K+1 letters of W₂(L<sup>r+1</sup>s, L<sup>r</sup>s)


If w₂ contains fewer complete chunks than w₃, we are done.
If w₂ contains fewer complete chunks (L...Ls) than w₃, we are done.


If w₂ and w₃ (which have the same length) contain the same number of complete chunks, one case is (X denotes a chunk boundary, < > are chunk boundaries that are also the boundary of the word, [] are non-chunk-boundary word boundaries.)
If w₂ and w₃ (which have the same length) contain the same number of complete chunks, one case is (X denotes a chunk boundary, < > are chunk boundaries that are also the boundary of the word, [] are non-chunk-boundary word boundaries.)