User:Inthar/MV3: Difference between revisions

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=== Lemma 1: The word made by any two of the step sizes is a MOS ===
=== Lemma 1: The word made by any two of the step sizes is a MOS ===
Suppose we have three sizes of a class, T1, T2, T3 of Y's and Z's.
Suppose that some class C in the word of Ys and Zs has three sizes, T1, T2, T3.


Assume T1, T2, T3 occur within a contiguous string of Y's and Z's. Then you get a 4th variant of this class (within the whole scale) by using a string of the same length including an X.
Assume T1, T2, T3 occur within a contiguous string of Y's and Z's. Then you get a 4th variant of this class (within the whole scale) by using a string of the same length including an X.


So it's pretty obvious that you have to have MV2 within a contiguous string, but what about the whole string minus the X's?
So it's pretty obvious that you have to have MV2 within a contiguous string, but what about the whole string minus the X's?
This part needs to be more careful, taking into account where X can appear:


If the occurrence of any class has an X inserted in the middle, then we can scoot it left or right until we have one of T1(possibly with inserted X's)+X, T2(possibly with inserted X's)+X, or T3 (possibly with inserted X's)+X. Scoot the string with the least X's to the left and you lose the X on the right, and gain another non-X letter on the left so you get a fourth variant of this interval class that contains T1 + X, a contradiction. (Check this again...)
If the occurrence of any class has an X inserted in the middle, then we can scoot it left or right until we have one of T1(possibly with inserted X's)+X, T2(possibly with inserted X's)+X, or T3 (possibly with inserted X's)+X. Scoot the string with the least X's to the left and you lose the X on the right, and gain another non-X letter on the left so you get a fourth variant of this interval class that contains T1 + X, a contradiction. (Check this again...)