Metallic MOS: Difference between revisions
Cmloegcmluin (talk | contribs) |
Cmloegcmluin (talk | contribs) |
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| Line 774: | Line 774: | ||
3L+2s&:2L+s \\ | 3L+2s&:2L+s \\ | ||
5L+3s&:3L+2s \\ | 5L+3s&:3L+2s \\ | ||
&\vdots | |||
\end{cases} | \end{cases} | ||
\end{align} | \end{align} | ||
| Line 785: | Line 785: | ||
<math> | <math> | ||
\begin{cases} | |||
L \\ | L \\ | ||
L+s \\ | L+s \\ | ||
| Line 790: | Line 791: | ||
3L+2s \\ | 3L+2s \\ | ||
5L+3s \\ | 5L+3s \\ | ||
\vdots | |||
\end{cases} | |||
</math> | </math> | ||
| Line 798: | Line 800: | ||
<math> | <math> | ||
\begin{cases} | |||
s \\ | s \\ | ||
L \\ | L \\ | ||
| Line 803: | Line 806: | ||
2L+s \\ | 2L+s \\ | ||
3L+2s \\ | 3L+2s \\ | ||
\vdots | |||
\end{cases} | |||
</math> | </math> | ||
Find any <span><math>s</math></span> in the horogram and observe how it gets split up as we iterate through the scale sequence. In the next iteration, <span><math>s</math></span> will be replaced with <span><math>L</math></span>. After two iterations, the original <span><math>s</math></span> interval is now represented by an <span><math>L</math></span> and an <span><math>s</math></span>. And so forth. | Find any <span><math>s</math></span> in the horogram and observe how it gets split up as we iterate through the scale sequence. In the next iteration, <span><math>s</math></span> will be replaced with <span><math>L</math></span>. After two iterations, the original <span><math>s</math></span> interval is now represented by an <span><math>L</math></span> and an <span><math>s</math></span>. And so forth. | ||