Delta-rational chord: Difference between revisions

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sympy.nonlinsolve([err_squared_x, err_squared_y], [x, y])
sympy.nonlinsolve([err_squared_x, err_squared_y], [x, y])
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This gives a unique solution, which is the global minimum.
The unique solution with x > 0 is
<math>
\displaystyle { \left( \frac{2 \delta_{1} + \delta_{3} + \frac{2 \left(- 2 \delta_{1}^{2} f_{1} + \delta_{1}^{2} f_{2} + \delta_{1}^{2} f_{3} - \delta_{1} \delta_{3} f_{1} + \delta_{1} \delta_{3} f_{2} - \delta_{1} \delta_{3} f_{3} + \delta_{1} \delta_{3} + \delta_{3}^{2} f_{2} - \delta_{3}^{2}\right)}{2 \delta_{1} f_{1} - 2 \delta_{1} - \delta_{3} f_{2} + \delta_{3} f_{3}}}{f_{2} + f_{3} - 2}, \  \frac{- 2 \delta_{1}^{2} f_{1} + \delta_{1}^{2} f_{2} + \delta_{1}^{2} f_{3} - \delta_{1} \delta_{3} f_{1} + \delta_{1} \delta_{3} f_{2} - \delta_{1} \delta_{3} f_{3} + \delta_{1} \delta_{3} + \delta_{3}^{2} f_{2} - \delta_{3}^{2}}{2 \delta_{1} f_{1} - 2 \delta_{1} - \delta_{3} f_{2} + \delta_{3} f_{3}}\right).}
</math>


=== Partially DR (arbitrary) ===
=== Partially DR (arbitrary) ===