The Riemann zeta function and tuning/Vector's derivation: Difference between revisions

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Now, this is a rather annoying function to work with for math reasons, so it might be useful to replace the "zigzag" that we use as our error function with a "smoother" alternative. The most obvious answer is cosine:
Now, this is a rather annoying function to work with for math reasons, so it might be useful to replace the "zigzag" that we use as our error function with a "smoother" alternative. The most obvious answer is cosine:


[https://www.desmos.com/calculator/deafikrhvg <nowiki>$$ \mu_{b} \left(\sigma, x \right) = \sum_{k=1}^{\infty}\frac{\cos\left(\log_{2}\left(k\right)\tau x\right)}{k^{\sigma}} $$</nowiki>]
[https://www.desmos.com/calculator/deafikrhvg <nowiki>$$ \mu_{a} \left(\sigma, x \right) = \sum_{k=1}^{\infty}\frac{\cos\left(\log_{2}\left(k\right)\tau x\right)}{k^{\sigma}} $$</nowiki>]




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Let's clean up the function by removing the scale factors on x. This just scales the function's inputs from EDO to [[Zetave|EDZ]], and these can be added back later to go back to EDO.
Let's clean up the function by removing the scale factors on x. This just scales the function's inputs from EDO to [[Zetave|EDZ]], and these can be added back later to go back to EDO.


[https://www.desmos.com/calculator/26ypbwbglg <nowiki>$$ \mu_{c} \left(\sigma, x \right) = \sum_{k=1}^{\infty}\frac{\cos (\ln\left(k\right)x)}{k^{\sigma}} $$</nowiki>]
[https://www.desmos.com/calculator/26ypbwbglg <nowiki>$$ \mu_{b} \left(\sigma, x \right) = \sum_{k=1}^{\infty}\frac{\cos (\ln\left(k\right)x)}{k^{\sigma}} $$</nowiki>]